Aptitude General Mental Ability

Clocks

Clock questions for CGPSC CSAT: angle between the hands, overlaps, right angles, mirror images and fast or slow clocks, with exact formulas.

11 min read Updated Oct 2026 #clocks#angle between hands#mirror image

Prerequisites

  • Fractions and mixed numbers: \( \frac{240}{11} = 21\frac{9}{11} \) should feel routine.
  • Speed as “distance per unit time” — clock hands are just two runners on a circular track (see Basic Numeracy).
  • Calendars is the companion topic in General Mental Ability.

The Hook: Two Runners on a Round Track

Connect

Look at the clock on an exam-hall wall. The minute hand sprints round the dial once an hour; the hour hand barely moves. At 12:00 they stand together. When will they meet again?

Most people say “1:05”. The real answer is \( 1{:}05\frac{5}{11} \) — a little later, because while the minute hand was catching up, the hour hand kept creeping forward.

The question this page answers: how do you find the angle between the hands at any time, the times when they meet, cross at right angles or point in opposite directions, and what a fast or slow clock really shows?

Why it matters for CGPSC: clock (घड़ी) questions in Prelims Paper II use a handful of exact formulas. Options are usually close fractions like \( 21\frac{9}{11} \) and \( 21\frac{3}{11} \), so the formula — not estimation — decides the mark.

How Fast the Hands Move

The dial is 360°, divided into 60 minute-spaces (6° each) and 12 hour-marks (30° each).

HandFull turnSpeed
Minute hand60 minutes6° per minute
Hour hand12 hours = 720 minutes0.5° per minute (30° per hour)
Minute hand relative to hour hand—5.5° per minute (55 minute-spaces gained in 60 minutes)

The Angle Between the Hands

At \( H \) hours and \( M \) minutes:

$$\boxed{\theta = \left|\,30H - \frac{11}{2}M\,\right|}$$

If \( \theta \) comes out above 180°, the smaller angle is \( 360^\circ - \theta \).

TimeCalculationAngle
3:40\( \lvert 90 - 220 \rvert \)130°
7:20\( \lvert 210 - 110 \rvert \)100°
2:30\( \lvert 60 - 165 \rvert \)105°
5:30\( \lvert 150 - 165 \rvert \)15°
9:15\( \lvert 270 - 82.5 \rvert = 187.5 \) → \( 360 - 187.5 \)172.5°
10:10\( \lvert 300 - 55 \rvert = 245 \) → \( 360 - 245 \)115°
The hour hand moves too
At 5:30 the hands are not together on the 6: the hour hand is halfway between 5 and 6. The angle is 15°, not 0°. The formula takes care of this automatically.

When Do the Hands Meet, Cross or Oppose?

The minute hand gains 5.5° (or \( \frac{11}{12} \) of a minute-space) every minute. Between \( H \) and \( H + 1 \) o’clock, the hands are \( k \) minute-spaces apart at

$$\boxed{M = (5H \pm k)\times\frac{12}{11}\ \text{minutes past } H}$$
Position\( k \) (minute-spaces)Example
Coincide (together)0Between 4 and 5: \( 20\times\frac{12}{11} = 21\frac{9}{11} \) min past 4
Right angle (90°)15Between 3 and 4: \( 30\times\frac{12}{11} = 32\frac{8}{11} \) min past 3 (and exactly 3:00)
Opposite (180°)30Between 4 and 5: \( 50\times\frac{12}{11} = 54\frac{6}{11} \) min past 4

Take \( 5H + k \) and \( 5H - k \); keep only the answers between 0 and 60.

Worked example

At what time between 2 and 3 o’clock are the hands at right angles?

\( 5H = 10 \), \( k = 15 \). \( (10 + 15)\times\frac{12}{11} = \frac{300}{11} = 27\frac{3}{11} \). The other value, \( (10 - 15) \), is negative, so there is only one right angle between 2 and 3: at \( 2{:}27\frac{3}{11} \).

How often in a day

The hands coincide every \( \frac{720}{11} = 65\frac{5}{11} \) minutes, not every 60.

EventIn 12 hoursIn 24 hours
Hands coincide1122
Hands opposite (180°)1122
Hands in a straight line (together or opposite)2244
Hands at right angles2244
Why 11, not 12, and why 22, not 24
Between 11 and 1 o’clock the hands meet only once — at 12:00 — so 12 hours give 11 meetings. Similarly, between 2 and 4 there are only 3 right angles (\( 2{:}27\frac{3}{11} \), 3:00 and \( 3{:}32\frac{8}{11} \)) instead of 4, and the same happens between 8 and 10. That leaves 22 right angles in 12 hours.

Mirror Images

A clock seen in a vertical mirror shows a time that, added to the real time, makes 12 hours:

$$\boxed{\text{Mirror time} = 11{:}60 - \text{actual time}}$$

For times from 12:00 to 12:59, use \( 23{:}60 \) instead.

Actual timeMirror shows
3:408:20
8:153:45
10:351:25
12:2011:40
6:00 or 9:006:00 or 3:00

The rule works both ways: if the mirror shows 4:20, the actual time is \( 11{:}60 - 4{:}20 = 7{:}40 \).

Fast and Slow (Faulty) Clocks

A gaining or losing clock shows the correct time again when its total error reaches 12 hours (720 minutes) on a 12-hour dial:

$$\boxed{\text{Time to show correct time again} = \frac{720}{\text{gain or loss per hour (in minutes)}}\ \text{hours}}$$

A clock gaining 5 minutes every hour shows the correct time again after \( \frac{720}{5} = 144 \) hours = 6 days.

Worked example: what the fast clock really means

A clock is set right at 8 a.m. It gains 10 minutes in every 24 hours. What is the true time when it shows 1 p.m. the next day?

From 8 a.m. to 1 p.m. the next day, the clock shows 29 hours. The clock runs 24 h 10 min (\( 24\frac{1}{6} \) h) for every 24 true hours, so

true time elapsed \( = 29\times\frac{24}{24\frac{1}{6}} = 28.8 \) hours \( = 28 \) h 48 min.

True time \( = \) 8 a.m. \( + \) 28 h 48 min \( = \) 12:48 p.m. the next day.

Worked example: hands meeting too early

The hands of a clock coincide every 64 minutes of true time. How much does the clock gain or lose in a day?

In a correct clock they coincide every \( 65\frac{5}{11} \) minutes. This clock completes those \( 65\frac{5}{11} \) clock-minutes in only 64 true minutes, so it gains \( \frac{16}{11} \) minutes every 64 minutes.

Gain per day \( = \frac{16}{11}\times\frac{1440}{64} = \frac{360}{11} = 32\frac{8}{11} \) minutes.

Memory Tricks

Anchor these
  • “Thirty H minus eleven-halves M” — the one formula for angles.
  • “Six, half, five-and-a-half” — degrees per minute for the minute hand, hour hand and their difference.
  • “12 by 11” — every meeting / right-angle / opposite time is a minute-space count multiplied by \( \frac{12}{11} \).
  • “11-22-44” — 11 meetings in 12 hours, 22 in a day, and 44 right angles (or straight lines) in a day.
  • Mirror: “eleven-sixty minus”.

Don’t Confuse

ThisvsThat
Hands coincide 22 times a dayHands at right angles 44 times a day
Hands opposite 22 times a dayHands in a straight line (together or opposite) 44 times a day
Hands meet every \( 65\frac{5}{11} \) min (correct clock)Meeting every 64 min → clock gains
Mirror time \( = 11{:}60 - \) timeAngle \( = \lvert 30H - 5.5M \rvert \)

Common Mistakes

Trap 1: Freezing the hour hand
At 3:40 the hour hand is not on 3 — it has moved \( 40\times 0.5 = 20^\circ \) past it. Ignoring this gives 140° instead of the correct 130°.
Trap 2: Counting 24 meetings in a day
The hands meet 22 times in 24 hours, not 24. The intuitive “once an hour” is the option examiners rely on.
Trap 3: Reporting the larger angle
If the formula gives more than 180°, subtract from 360°. “The angle between the hands” means the smaller angle unless the question says otherwise.

Practice

Level 1: Foundation

  1. Through how many degrees does the hour hand move in 20 minutes?
  2. Find the angle between the hands at 6:00 and at 3:00.
  3. How many times do the hands coincide in a day?
  4. A clock seen in a mirror shows 9:00. What is the actual time?
Answers
  1. \( 20\times 0.5 = 10^\circ \).
  2. 180° and 90°.
  3. 22 times.
  4. \( 11{:}60 - 9{:}00 = \) 3:00.

Level 2: Prelims MCQs

Q1. Match List I (time) with List II (angle between the hands):

List IList II
A. 3:401. 15°
B. 9:152. 105°
C. 2:303. 130°
D. 5:304. 172.5°

(a) A-3, B-4, C-1, D-2 (b) A-3, B-4, C-2, D-1 (c) A-4, B-3, C-2, D-1 (d) A-2, B-4, C-3, D-1

Answer: (b) A-3, B-4, C-2, D-1
Using \( \lvert 30H - 5.5M \rvert \): 3:40 → \( \lvert 90 - 220 \rvert = 130^\circ \); 9:15 → \( \lvert 270 - 82.5 \rvert = 187.5 \), smaller angle \( 172.5^\circ \); 2:30 → \( \lvert 60 - 165 \rvert = 105^\circ \); 5:30 → \( \lvert 150 - 165 \rvert = 15^\circ \).

Q2. At what time between 4 and 5 o’clock will the hands of a clock coincide?

(a) \( 21\frac{9}{11} \) minutes past 4 (b) 20 minutes past 4 (c) \( 22\frac{2}{11} \) minutes past 4 (d) \( 21\frac{3}{11} \) minutes past 4

Answer: (a) 21 9/11 minutes past 4
At 4:00 the minute hand is 20 minute-spaces behind. It gains \( \frac{11}{12} \) of a space per minute, so it catches up in \( 20\times\frac{12}{11} = \frac{240}{11} = 21\frac{9}{11} \) minutes. Option (b) forgets that the hour hand keeps moving.

Q3. The reflection of a wall clock in a plane mirror shows 4:20. What is the actual time?

(a) 8:40 (b) 7:20 (c) 8:20 (d) 7:40

Answer: (d) 7:40
Actual time \( = 11{:}60 - 4{:}20 = 7{:}40 \). Check: \( 7{:}40 + 4{:}20 = 12{:}00 \).

Q4. Consider the following statements about a correctly working clock:

  1. The hands coincide 22 times in a day.
  2. The hands are at right angles 48 times in a day.
  3. The hands are in a straight line (together or opposite) 44 times in a day.

Which of the statements given above is/are correct?

(a) 1 only (b) 1 and 2 only (c) 1 and 3 only (d) 2 and 3 only

Answer: (c) 1 and 3 only
The hands coincide 22 times and are opposite 22 times a day, so they are in a straight line \( 22 + 22 = 44 \) times (1 and 3 correct). Right angles occur 44 times a day, not 48, because between 2 and 4 and between 8 and 10 there are only three right angles instead of four (in each half of the day).

Q5. A clock is set right at 8 a.m. and gains 10 minutes in every 24 hours. What is the true time when it shows 1 p.m. on the following day?

(a) 12:50 p.m. (b) 12:48 p.m. (c) 12:45 p.m. (d) 12:40 p.m.

Answer: (b) 12:48 p.m.
Clock time elapsed = 29 hours. The clock shows \( 24\frac{1}{6} \) hours for every 24 true hours, so true time elapsed \( = 29\times\frac{24}{24\frac{1}{6}} = 28.8 \) h = 28 h 48 min. 8 a.m. + 28 h 48 min = 12:48 p.m. the next day. Option (a) subtracts the full day’s 10-minute gain, but only 28.8 true hours have passed.

Level 3: Speed Drill — Solve in 60 Seconds

Each item should take under 60 seconds with the formulas on this page. In the reasoning part of Mains Paper IV (GS-II), write the formula before substituting values.

  1. Angle between the hands at 7:20?
  2. Angle between the hands at 9:45?
  3. At what time between 2 and 3 are the hands at right angles?
  4. At what time between 4 and 5 are the hands opposite each other?
  5. Actual time 10:35 — what does the mirror show?
  6. A clock gains 5 minutes every hour. After how many hours will it next show the correct time?
  7. The hands of a clock coincide every 64 minutes. How much does the clock gain in a day?
Answers with the formula used
  1. 100° — \( \lvert 210 - 110 \rvert \).
  2. 22.5° — \( \lvert 270 - 247.5 \rvert \).
  3. \( 2{:}27\frac{3}{11} \) — \( (10 + 15)\times\frac{12}{11} \).
  4. \( 4{:}54\frac{6}{11} \) — \( (20 + 30)\times\frac{12}{11} \).
  5. 1:25 — \( 11{:}60 - 10{:}35 \).
  6. 144 hours (6 days) — \( \frac{720}{5} \).
  7. \( 32\frac{8}{11} \) minutes — \( \frac{16}{11}\times\frac{1440}{64} \).

Quick Revision Table

IdeaFormula / Fact
Hand speedsMinute 6°/min; hour 0.5°/min; relative 5.5°/min
Angle\( \lvert 30H - 5.5M \rvert \); if above 180°, take \( 360 - \theta \)
\( k \) spaces apart between H and H+1\( (5H \pm k)\times\frac{12}{11} \) min past H
Coincide interval\( 65\frac{5}{11} \) min
Per day22 coincide, 22 opposite, 44 right angles, 44 straight lines
Mirror image\( 11{:}60 - \) time (\( 23{:}60 \) for 12:xx)
Correct again\( \frac{720}{\text{gain per hour}} \) hours
Faster meetings than \( 65\frac{5}{11} \) minClock gains

Key Takeaways

Key Takeaways
  1. The angle is \( \lvert 30H - 5.5M \rvert \) — the hour hand moves half a degree every minute, never ignore it.
  2. Every meeting, right-angle or opposite time is \( (5H \pm k)\times\frac{12}{11} \) minutes past \( H \), with \( k = 0, 15, 30 \).
  3. In a day: 22 meetings, 22 oppositions, 44 right angles.
  4. Mirror time \( = 11{:}60 - \) actual time.
  5. A faulty clock shows the right time again after a total error of 720 minutes; meetings faster than every \( 65\frac{5}{11} \) minutes mean the clock gains.

What’s Next

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